Consider the reaction between reactants S & O2

2S(s) + 3 O2(g) ==> 2 SO3(g)

If a reactant vessel initially contains 5 mol S and 9 mol O2, how many moles of S, O2 and SO3 will be in the reaction vessel once the reactants have reached as much as possible? Assume 100% actual yield
Lost again

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You need to go back and look at your posts. I worked this earlier IN GREAT DETAIL.
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