Consider the reaction between reactants S & O2
2S(s) + 3 O2(g) ==> 2 SO3(g)
If a reactant vessel initially contains 5 mol S and 9 mol O2, how many moles of S, O2 and SO3 will be in the reaction vessel once the reactants have reached as much as possible? Assume 100% actual yield
Lost again
1 answer
You need to go back and look at your posts. I worked this earlier IN GREAT DETAIL.