4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g).
mols CO2 = 75/22.4 = 3.34
mols KO2 needed = 3.34 mols CO2 x (4 mols KO2/2 mols CO2) =?
The grams KO2 = mols KO2 x molar mass KO2
Post your work if you get stuck.
Consider the reaction
4 KO2(s) + 2 CO2(g) →
2 K2CO3(s) + 3 O2(g).
How much KO2 is needed to react with 75.0 L
of carbon dioxide at STP?
1 answer