Consider the reaction:
2Mg + O2 ------> 2MgO
The reaction is at equilibrium, the concentration of MgO is found to be 0.5.
What is the concentration of Mg and O2?
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Keq is not given... using the ICE table, I ended up with the following:
Keq = [MgO]^2 / [Mg]^2 * [O2]
Keq = [0.5]^2 / [2x - 0.5]^2 * [x - 0.5]
Keq = 0.25 / 2x(x - 1) + 0.25
Not sure what to do.. or if I'm even going in the right direction
1 answer