NH3 = 14 + 3 = 17 grams/mol
203.5/17 = 12 mols of NH3
so
12 mols of HCN result
HCN = 1 + 12 + 14 = 27 grams/mol
so 12 * 27 grams HCN
Consider the reaction: 2CH4(g) + 3O2(g) + 2NH3(g) --> 2HCN(g) + 6H2O(g)
If 203.5 g NH3 is reacted with excess CH4 and O2, what mass in grams of HCN can be produced?
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