mols B2H6 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols B2H6 to mols NaBH4.
Now convert mols NaBH4 to volume with
M = mols/L solution. You know M and mols, solve for L solution and convert to mL.
Consider the reaction:
2 NaBH4(aq) + H2SO4(aq) → 2 H2(g) + Na2SO4(aq) + B2H6(g)
What volume, in mL, of a 0.500 M solution of NaBH4 is required to produce 0.529 g of B2H6? H2SO4 is present in excess.
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