Consider the polynomial division (x^3+5x^2+4x+18)÷(x+5)

. Give the quotient with the remainder expressed as a fraction.

1 answer

To divide the polynomial (x^3 + 5x^2 + 4x + 18) by (x + 5), we use long division:

x^2 - 4x + 16
_________________________
x + 5 | x^3 + 5x^2 + 4x + 18
- (x^3 + 5x^2)
____________
- x^2 + 4x
- (- x^2 - 5x)
_____________
9x + 18
- (9x + 45)
____________
- 27
The quotient is x^2 - 4x + 16 and the remainder is -27. So, the division (x^3 + 5x^2 + 4x + 18) ÷ (x + 5) can be expressed as:

(x^2 - 4x + 16) - 27 / (x + 5)