1: Mg (s) | Mg2+ (1 M) || Al3+ (1 M) | Al (s)
2: Mg (s) + 2 Al3+ (aq) -> Mg2+ (aq) + 2 Al (s)
3: Anode: Mg (s) -> Mg2+ (aq) + 2e^-
Cathode: Al3+ (aq) + 3e^- -> Al (s)
4: To calculate Ecell, we need to find the standard reduction potentials for each half reaction. The standard reduction potential for Mg2+ is -2.37 V and for Al3+ is -1.66 V.
Ecell = Eocathode - Eoanode
Ecell = -1.66 V - (-2.37 V)
Ecell = 0.71 V
Therefore, the Ecell for the galvanic cell of Mg and Al is 0.71 V.
Consider the lone notation of the galvanic cell of Mg and Al ,
1: sketch the galvanic cell
2: give the overall balance cell reaction
3: half reaction for the galvanic cell line notation
4: calculate Ecell
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