(a) Find the y-intercept for the given line.
(b)Find the slope for a line parallel to the given line.
(c) Find the slope for a line perpendicular to the given line.
Consider the line with equation
5x – 2y = 10.
(a) Find the y-intercept for the given line.
(b) Find the slope for a line parallel to the given line.
(c) Find the slope for a line perpendicular to the given line.
4 answers
y intercept is when x = 0
-2y = 10
y = -5
2 y = 5 x - 10
y = (5/2) x = 5
so m, the slope, = (5/2)
m'= -1/m
m' = -2/5
-2y = 10
y = -5
2 y = 5 x - 10
y = (5/2) x = 5
so m, the slope, = (5/2)
m'= -1/m
m' = -2/5
This is interesting, I got the first one correct for y = -5 because x = 0 but still do not get how you come up with 5/2 for the slope of the parallel line and the slope of the perpendicular one either? Can you please explain. Thanks!
how did you come up with (5/2)
0 answers