To approximate \(\sqrt[5]{1511}\) using the function \(g(x) = 15x\), we need to find the values of \(x\) that make \(g(x)\) approach 1511.
- Start with \(x = 3\): \[ g(3) = 15 \cdot 3 = 45 \]
Now, we can choose the next five rational values that are greater than 3. We will increment \(x\) to find the next values.
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Next, we'll test \(x = 4\): \[ g(4) = 15 \cdot 4 = 60 \]
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Next, \(x = 5\): \[ g(5) = 15 \cdot 5 = 75 \]
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Next, \(x = 6\): \[ g(6) = 15 \cdot 6 = 90 \]
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Next, \(x = 7\): \[ g(7) = 15 \cdot 7 = 105 \]
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Finally, \(x = 8\): \[ g(8) = 15 \cdot 8 = 120 \]
Thus, the next five x-values after 3 are:
The answer is: 3, 4, 5, 6, 7, 8