To approximate \( 15\sqrt{11} \) using the function \( g(x) = 15x \), we can first find \( \sqrt{11} \). Since you started with \( x = 3 \), we can look at values around \( \sqrt{11} \).
We know that \( \sqrt{11} \) is approximately equal to \( 3.3166 \), so to approximate this with \( g(x) \), we will use x-values close to this number.
Starting from \( x = 3 \), let's adjust by adding a fraction of the difference to move towards \( \sqrt{11} \):
- First value: \( x_1 = 3.1 \)
- Second value: \( x_2 = 3.2 \)
- Third value: \( x_3 = 3.3 \)
- Fourth value: \( x_4 = 3.4 \)
- Fifth value: \( x_5 = 3.5 \)
The next five \( x \)-values that we can use to approximate \( 15\sqrt{11} \) are:
- \( 3.1 \)
- \( 3.2 \)
- \( 3.3 \)
- \( 3.4 \)
- \( 3.5 \)
Using these \( x \)-values in the function \( g(x) = 15x \) will yield approximations for \( 15\sqrt{11} \).