If the point (2 + c, y) is on the graph of f(x) = x(x-4), we can substitute (2 + c) for x in the equation and solve for y.
f(2 + c) = (2 + c)((2 + c) - 4)
Simplifying,
f(2 + c) = (2 + c)(c - 2)
Expanding,
f(2 + c) = 2c + c^2 - 4
Therefore, the point (2 + c, y) on the graph of f(x) is (2 + c, 2c + c^2 - 4).
To find another point on the graph of f(x), we can substitute (2 + c + d) for x in the equation and solve for y:
f(2 + c + d) = (2 + c + d)((2 + c + d) - 4)
Simplifying,
f(2 + c + d) = (2 + c + d)(c + d - 2)
Expanding,
f(2 + c + d) = 2c + 2d + c^2 + cd + d^2 - 4
Therefore, the point (2 + c + d, y) on the graph of f(x) is (2 + c + d, 2c + 2d + c^2 + cd + d^2 - 4).
Consider the function f(x) = x(x-4).
If the point (2 + c, y) is on the graph of f(x), the following point will also be on the graph of f(x)
1 answer