You know that points of inflection are where f"(x) = 0
Assuming you meant f(x) = x^2/(6x^2+8) then
f'(x) = 4x/(3x^2+4)^2
f"(x) = -4(9x^2-4)/(4x^2+4)^3
So, where is f"(x) = 0?
Consider the function
f(x)=x^2/ 6x^2+8.
List the x values of the inflection points of f. If there are no inflection points, enter 'NONE'.
1 answer
1 answer