Consider the function f(x) whose second derivative is f''(x)=2x+5sin(x).
If f(0)=4 and f'(0)=3, then what is f(4)?
2 answers
f(4) = 4 + 3*4 + (1/2)*(2*4 + 5*sin(4)) = 28.9
AAAaannndd the bot gets it wrong yet again!
f" = 5sinx + 2x
f' = -5cosx + x^2 + 8
f = -5sinx + 1/3 x^3 + 8x + 4
f(4) = -5sin4 + 64/3 + 32 + 4 = 61.117
f" = 5sinx + 2x
f' = -5cosx + x^2 + 8
f = -5sinx + 1/3 x^3 + 8x + 4
f(4) = -5sin4 + 64/3 + 32 + 4 = 61.117