Consider the function f(x)=sin(1/x)

Find a sequence of x-values that approach 0 such that

sin (1/x)=0
sin (1/x)=1
sin (1/x)=-1

Is sin sin (1/x)=0 and sin (1/x)=-1 does not exist.

What is sin (1/x)=1 then.

How would I show the sequence of values, any help would be greatly appreciated.

Similar Questions
  1. Consider the function f(x)=sin(1/x)Find a sequence of x-values that approach 0 such that sin (1/x)=0 sin (1/x)=1 sin (1/x)=-1 Is
    1. answers icon 1 answer
  2. f(x)=cos(1/x)Find a sequence for x-values that approach 0 such that cos(1/x)=0.
    1. answers icon 1 answer
  3. Consider the function f(x)=sin(1/x)Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact
    1. answers icon 0 answers
  4. Consider the function f(x)=sin(1/x)Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact
    1. answers icon 1 answer
more similar questions