f(-1) = 3-1-1+1 = 2
f(-2) = 19
slope = (2-19)/1 = -17 agree
f'(x) = -9 x^2 - 2 x + 1
for what values of x is that -17?
-9 x^2 - 2 x + 1 = -17
9 x^2 + 2 x - 18 = 0
x = [-2 +/- sqrt (4+648)]/18
= 1.3 or -1.53
-1,53 is in the domain
check it by calculating
f'(1.53)
Consider the function
f(x)=–3x3–1x2+1x+1Find the average slope of this function on the interval (–2–1).
By the Mean Value Theorem, we know there exists a c in the open interval (–2–1) such that f(c) is equal to this mean slope. Find the value of c in the interval which works
I found the mean which is -17 but I can't get the C. I don't know what im doing wrong
1 answer
1 answer