Consider the function f ( x ) = 3 − 5 x^2 on the interval [ − 2 , 8 ] . Find the average or mean slope of the function on this interval, i.e.

f(8)-f(-2)/8-(-2)=

By the Mean Value Theorem, we know there exists a c in the open interval ( − 2 , 8 ) such that f ' ( c ) is equal to this mean slope. For this problem, there is only one c that works. Find it.

Answer with explanation please and thanks!

1 answer

really? They gave you the actual formula.
Just evaluate m = (f(8)-f(-2))/(8-(-2)) = ___
now, since f'(x) = -10x, you want to find c such that
-10c = m
c = -m/10
Similar Questions
  1. the function =-x^2+4x-3 is graphed in the xy-corrdinate plane as shown.Based on the graph of the function, which of the
    1. answers icon 1 answer
  2. 6)The function f(x)=4x3−18x2−480x−2 is decreasing on the interval ? Enter your answer using the interval notation for open
    1. answers icon 0 answers
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions