To determine which operator can be inserted between the expressions \(-6 + 3 \cdot 5\) and \(16 - \sqrt{16} + 32 \div 8\), we need to evaluate both expressions.
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Calculate the left-side expression \(-6 + 3 \cdot 5\):
- First calculate \(3 \cdot 5 = 15\).
- Then, \(-6 + 15 = 9\).
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Calculate the right-side expression \(16 - \sqrt{16} + 32 \div 8\):
- First calculate \(\sqrt{16} = 4\).
- Then calculate \(32 \div 8 = 4\).
- Now substitute these values: \(16 - 4 + 4\).
- This simplifies to \(16 - 4 = 12\), and then \(12 + 4 = 16\).
Now we compare the two results:
- Left-hand side: \(9\)
- Right-hand side: \(16\)
Now, we insert the operators:
- Compare \(9\) and \(16\):
- \(9 < 16\) is true, so you can use the less than operator \(<\).
Therefore, the correct answer is:
< (less than)