Consider the following scenarioA sample of radioactive material has a decay constant of 0.04 per hourIf there are initially 500 grams of the material, how much will remain after 3 hours?

Answer 1

To solve this problem, we can use the formula for radioactive decay:

N(t) = N0 * e^(-λt)

Where:
N(t) = the amount of material remaining after time t
N0 = the initial amount of material
λ = the decay constant
t = time in hours

Given:
N0 = 500 grams
λ = 0.04 per hour
t = 3 hours

Plugging in the values:

N(3) = 500 * e^(-0.04 * 3)
N(3) = 500 * e^(-0.12)
N(3) = 500 * 0.889
N(3) = 444.44 grams

Therefore, after 3 hours, there will be approximately 444.44 grams of the radioactive material remaining.