rate = k*[A]o[B]2
OR you may omit the A terms since A raised to the zero power is 1. The "trick" to the problem, I suspect, is that many will write it as (A)^2*(B)^3.
Consider the following reaction was found to be the 0th order to A and 2nd order to B.
2A(cr) + 3B(aq) -->A2B3(cr)
Write a rate law equation for the reaction rate of A with B.
4 answers
Ok, thanks.
Couple follow ups:
Q1: If [A] is doubled how does the reaction rate change?
A: I put no change because 0th order cancels it out.
Q2: If [B] is doubled how does the reaction rate change?
A: I put it increases by a factor of 4 because of the squared term.
Q3: How would increase pressure effect the reaction rate?
A:???
Couple follow ups:
Q1: If [A] is doubled how does the reaction rate change?
A: I put no change because 0th order cancels it out.
Q2: If [B] is doubled how does the reaction rate change?
A: I put it increases by a factor of 4 because of the squared term.
Q3: How would increase pressure effect the reaction rate?
A:???
Now that I look at Q3 I am thinking it is going to increase it, but not sure by what factor?
The answer to A is correct since it's zero order with respect to A. The answer to B is correct since 2^2 = 4.
Look at the equation. A is Cr which I assume means crystalline and that means a solid. B is aq which I assume means a liquid and A2B3 is cr which again I assume is a solid. Pressure will have an effect if reactants or products are gases; however, pressure has no effect on solids and essentially no effect on liquids. So increased pressure, I think, will have no effect on the rate of this reaction. .
Look at the equation. A is Cr which I assume means crystalline and that means a solid. B is aq which I assume means a liquid and A2B3 is cr which again I assume is a solid. Pressure will have an effect if reactants or products are gases; however, pressure has no effect on solids and essentially no effect on liquids. So increased pressure, I think, will have no effect on the rate of this reaction. .