Consider the following reaction:
Find the equilibrium partial pressures of A and B for each of the following different values of Kp. Assume that the initial partial pressure of B in each case is 1.0 atm, and that the initial partial pressure of A is 0.0 atm. Make any appropriate simplifying assumptions
Kp=1.6
Kp=1.0*10^-4
Kp=1.2*10^5
I need to get this question immediately!! I've tried to figure this out for hours now. I've tried multiple ICE tables. Once I know how to do the first one I'm sure I can get the rest.
4 answers
What's the reaction equation?
Oops! I thought that was there. It is A(g)<-> 2B(g)
...........A ==> 2B
initial...0.....1.0
change....+p....-p
equil.....p.....1.0-p
Check that.
initial...0.....1.0
change....+p....-p
equil.....p.....1.0-p
Check that.
so this set up would be 1.6= (1-p)^2/p
which then turns to p^2+1.6p-1 then solve the quadratic equation?
which then turns to p^2+1.6p-1 then solve the quadratic equation?
1 answer