The expression for the equilibrium constant for this reaction would be K = [CH4O]/[CO][H2]^2.
Based on Le Chatelier's Principle, if the equilibrium constant K is relatively large, it means that the products are favored at equilibrium. This would suggest that the forward reaction is favored, indicating that the enthalpy change (∆H) is negative. Therefore, the most appropriate answer is negative.
Consider the following reaction:
CO(g) + 2H2(g) - CH4O (g)
Part: 0 / 5
K=2.3×104
Part 1 of 5
Write the expression for the equilibrium constant for this reaction.
Would you predict AH to be positive or negative? Select the single best answer.
zero
positive
negative
1 answer