Limiting reagent problem, I think, are easiest to do if you do TWO simple stoichiometry problems. The first time you use CaO and determine moles CaCO3 produced. The second time use 13.8 g CO2 and determine moles CaCO3 produced. The correct answer, in limiting reagent problems, is ALWAYS the smaller value and the reagent producing that smaller value is the limiting reagent. That value of CaCO3 produced will be the theoretical yield.
percent yield = (actual yield/theoretical yield)*100 = ??
(note: actual yield is 19.4 g from the problem.).
Consider the following reaction. CaO (s) + CO2 (g) = CaCO3 (s) A chemist allows 14.4 g of CaO and 13.8 g of CO2 to react. When the reaction is finished, the chemist collects 19.4 g of CaCO3. Determine the limiting reactant, theoretical yield, and percent yield for the reactio
options:
CaO; 32 g CaCO3; 60.6%
CaCO3; 25.7 g CaO; 45.5%
CaCO3; 67.2 g CaO; 28.9%
CaO; 25.7 g CaCO3; 75.5%
CaO; 15.0 g CaCO3; 129%
3 answers
afgs
wioeruwqe
2 answers