Consider the following reaction:
2HBr(g) = H2(g) + Br2 (g)
Part: 0 / 5
K=5.3×10-20
Part 1 of 5
Write the expression for the equilibrium constant for this reaction.
1 answer
K = [H2][Br2] / [HBr]^2
2HBr(g) = H2(g) + Br2 (g)
Part: 0 / 5
K=5.3×10-20
Part 1 of 5
Write the expression for the equilibrium constant for this reaction.
1 answer