The half-life for a first-order reaction is given by the equation:
t1/2 = ln(2) / k
where t1/2 is the half-life and k is the rate constant.
Rearranging this equation gives:
k = ln(2) / t1/2
Substituting the given half-life of 0.910 s, we get:
k = ln(2) / 0.910 s ≈ 0.762 s^-1
Therefore, the rate constant for the reaction is approximately 0.762 s^-1.
Consider the following reaction
2 N2O(g)--2NO(g)+ O2(g); rate = K[N2O]
If the half life for the reaction is 0.910 s,what is the rate constant
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