consider the following quadratic equation. solve the following equation. write your answer in reduced fraction form, if necessary. x^(2)-10x+25=0

Answer 1

To solve the quadratic equation x^2 - 10x + 25 = 0, we can use the quadratic formula x = (-b ± √(b^2 - 4ac)) / (2a).

In this case, a = 1, b = -10, and c = 25.

Plugging these values into the quadratic formula, we get:
x = (-(-10) ± √((-10)^2 - 4(1)(25))) / (2(1))
x = (10 ± √(100 - 100)) / 2
x = (10 ± √0) / 2

Since the square root of 0 is 0, we have:
x = (10 ± 0) / 2

Simplifying further:
x = 10 / 2 = 5 (repeated twice)

Therefore, the solutions to the quadratic equation x^2 - 10x + 25 = 0 are x = 5 and x = 5.