Consider the following partially completed frequency table:

Class xi fi
[87; 97) 92 3
[97; 107) 102 5
[107; 117) 112 9
[117; 127) 122 11
[127; 137) 132 2


Determine the arithmetic mean.

133.3333


120


113.3333


138.3333

1 answer

To determine the arithmetic mean, we need to first calculate the midpoint of each class interval, which is given by the formula xi = (lower bound + upper bound) / 2. Then we find the product of xi and fi for each class, sum them up, and divide by the total frequency.

The calculations are as follows:

(92*3) + (102*5) + (112*9) + (122*11) + (132*2) = 276 + 510 + 1008 + 1342 + 264 = 3400

Total frequency = 3 + 5 + 9 + 11 + 2 = 30

Arithmetic Mean = 3400 / 30 = 113.3333

Therefore, the arithmetic mean is 113.3333.

The correct answer is:

113.3333
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