Consider the following partially completed ANOVA, and answer the following: give the value of (C). / Beskou die onvoltooide ANOVA en beantwoord die volgende: gee die waarde van (C).

ANOVA

Source SS df MS Fstat Ftab
Treatment (A) 2 43 024.778 25.1754 (F)
Error 10 254 (C) (E)
Total (B) (D)

1 answer

To find the missing values in the ANOVA table, we can use the following relationships:

  1. Degrees of Freedom (df):

    • For Treatment: df = k - 1, where k is the number of treatments.
    • For Error: df = N - k, where N is the total number of observations and k is the number of treatments.
    • Total df = N - 1.
  2. Sum of Squares (SS):

    • Total SS = Treatment SS + Error SS.
    • SS values can be calculated as:
      • MS (Mean Square) = SS / df.
      • Therefore, SS = MS * df.
  3. F-statistic:

    • F-statistic = MS(Treatment) / MS(Error).

From the provided ANOVA table, we can see that:

  • For Treatment:

    • SS = A
    • df = 2
    • MS = 43,024.778
    • Fstat = 25.1754
  • For Error:

    • SS = 10,254
    • df = C
    • MS = E
  • Total:

    • SS = B
    • df = D

Steps to find missing values:

  1. Calculate Treatment SS (A): \[ A = MS_{Treatment} \times df_{Treatment} \] \[ A = 43,024.778 \times 2 \] \[ A = 86,049.556 \]

  2. Compute Total SS (B): \[ B = A + Error , SS = A + 10,254 \] \[ B = 86,049.556 + 10,254 = 96,303.556 \]

  3. Calculate Error df (C): Since we don’t have N, let’s express C in terms of N and k. We know: \[ Total , df = (N - 1) \] Since Total df = Treatment df + Error df: \[ C = N - k \] Given that Treatment df = 2, hence \( k = 3 \). Therefore: \[ Total , df = (N - 1) = (N - 3 + 2); \] So N = C + 1.

    The missing information remains about N; let’s estimate the Error df (C) directly depending on how many total treatments we might have.

  4. Using F-statistic: Calculate Error MS (E): \[ E = \frac{SS_{Error}}{df_{Error}} \] \[ \text{Given that } msTreatment = 43024.778, \text{ and Fstat = 25.1754} \] \[ \frac{43,024.778}{E} = 25.1754 \rightarrow E = \frac{43,024.778}{25.1754} \approx 1,706.166 \]

Thus, using \( C \): \[ 10,254 = E \times C, {1,706.166 \times C = 10,254 }. \]

  1. Solving for C: \[ C = \frac{10,254}{1,706.166} \approx 6 \]

So \( C \) = 6.

Final Values:

  • Treatment SS (A) = 86,049.556
  • Error df (C) = 6
  • Total SS (B) = 96,303.556

Now you have the value of C, which is 6.