Consider the following.

P(A) = 0.27 and P(B) = 0.36,
A and B are mutually exclusive events

(a) Find the probability P(A). (Give your answer correct to two decimal places.)

(b) Find the probability P(B). (Give your answer correct to two decimal places.)

(c) Find the probability P(A or B). (Give your answer correct to two decimal places.)

(d) Find the probability P(A and B). (Give your answer correct to two decimal places.)

3 answers

Hints:
P(A∪B)=P(A)+P(B)+P(A∩B)

So if any three of the four probabilities are known, we can find the fourth one.

Note:
Events A and B are mutually exclusive if and only if P(A∩B)=0.
sorry this has not helped me at all....I am so confused on this stuff...
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