clearly the common difference is 5, from the first two terms.
so, m-(k+1) = 5
now, the common ratio tells us that
m/(k+1) = 5k/m
solving both those equations, we get
(k,m) = (4,10)
and the terms are
0,5,10,20
and you can see the AP and GP
consider the following (k-4) ; (k+1) ;m ; 5k ... the first 3 terms are arithmetic the last 3terms are geometric. .. determine the values of m and k if both are positive integers
2 answers
You can calculated my question where ,asking like that ,consider the following term (k-4),(k-1),m,5k