Consider the following: h={(1,2),(2,4),(3,6),(-1,-2),(-2,-4)}.
a) Explain why h: ℤ --> ℤ does not describe h correctly.
I think this is probably because the range of the function h is finite or limited which means that we can't account for all possible integers. I am not sure if this is correct?
b) If the co-domain of h is the set {-4, -2, 0, 2, 4,... , 6}, is h onto? Why or why not?
I think that if the co-domain of h is the set given, then it would not be onto because the co-domain is not equal to the range of the function h. The range is missing a 0 and a -6. I'm not sure if my reasoning is correct either?
c) Find h(h(1)).
I think that h(h(1)) = h(2) = 4 ???
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good answers, but B is true because there are elements of the codomain which are not used. h is into, not onto.
Thank you so much for your help! I am just wondering if my answers for part a and c are correct?
yes - that's what "good answers" means ...
I don't understand how b is considered onto?
0 answers