Consider the following expressions:

Question

-6 + 3 x 5_____square root 16 + 32 divided by 8.

Which operator can be inserted to make the statement true?

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Answer 1

To evaluate the expression:

\[ -6 + 3 \times 5 \quad ____ \quad \sqrt{16} + \frac{32}{8} \]

let's first compute each side:

1. Left Side Calculation: \[ -6 + 3 \times 5 \] According to the order of operations, we perform the multiplication first: \[ 3 \times 5 = 15 \] Then, we add: \[ -6 + 15 = 9 \]

2. Right Side Calculation: \[ \sqrt{16} + \frac{32}{8} \] First, calculate the square root: \[ \sqrt{16} = 4 \] Next, divide: \[ \frac{32}{8} = 4 \] Now, add: \[ 4 + 4 = 8 \]

Now we have: \[ 9 \quad ____ \quad 8 \]

• We know that \( 9 > 8 \), so we can insert the "greater than" operator.

Thus, we conclude that the appropriate operator to insert is: \[

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