Let's evaluate both sides of the expression to find out which operator makes the statement true.
First, we calculate the left side:
\(-6 + 3 \cdot 5\)
Following the order of operations (PEMDAS/BODMAS), we calculate \(3 \cdot 5\) first:
\[ 3 \cdot 5 = 15 \]
Now substituting that back into the expression:
\[ -6 + 15 = 9 \]
So, the left side evaluates to \(9\).
Now, let's evaluate the right side:
\(\sqrt{16} + 32 \div 8\)
First, we calculate \(\sqrt{16}\):
\[ \sqrt{16} = 4 \]
Next, we calculate \(32 \div 8\):
\[ 32 \div 8 = 4 \]
Now substituting that back into the expression:
\[ 4 + 4 = 8 \]
So, the right side evaluates to \(8\).
Now we compare the two sides:
Left side: \(9\)
Right side: \(8\)
Now, we can determine the relation between the two values:
\(9\) is greater than \(8\).
Thus, we can insert the operator \(>\) (greater than) to make the statement true:
\(-6 + 3 \cdot 5 > 16 - \sqrt{16} + 32 \div 8\).
So, the answer is:
> greater than