Consider the following equilibrium:

CoCl42-(ac) + 6 H2O (l) = Co(H2O)62+ (ac) + 4 Cl-

what effect will adding NaOH have on the equilibrium and on K constant.

1 answer

the chemical reaction is the following:
(CoCl4)^2- (ac) + 6 H2O (l) = ( Co(H2O)6)^2 + (ac) + 4 Cl-

sorry it's not that understandable in the first post.