Consider the following equation, which represents the combustion of hydrogen sulfide.

Question

2H2S(g)+3O2(g)�¨2SO2(g)+2H2O(g)

What volume, in liters, of SO2 is formed when 120L of H2S(g) is burned? Assume that both gases are measured under the same conditions.

Answer 1

You should find the arrow key on your computer and use it.

When using gases at the same T and P one can use a shortcut procedure in which the volume (in L) is used directly as if it were mols.
So all you need to do is to convert 120 L H2S to SO2.

120 L SO2 x (2 mols SO2/2 mols H2S) \ 120 x 2/2 = 120 L SO2 formed.