Consider the following discrete probability distribution.



x 15 22 34 40
P(X = x) 0.16 0.40 0.25 0.19

a. Is this a valid probability distribution?

multiple choice
Yes, because the probabilities add up to 1.
No, because the gaps between x values vary.

b. What is the probability that the random variable X is less than 39? (Round your answer to 2 decimal places.)

c. What is the probability that the random variable X is between 9 and 27? (Round your answer to 2 decimal places.)

d. What is the probability that the random variable X is greater than 19? (Round your answer to 2 decimal places.)

1 answer

a. Yes, because the probabilities add up to 1.

b. To find the probability that X is less than 39, we need to sum up the probabilities for all x values less than 39.

P(X < 39) = P(X = 15) + P(X = 22) + P(X = 34)
= 0.16 + 0.40 + 0.25
= 0.81

Therefore, the probability that X is less than 39 is 0.81.

c. To find the probability that X is between 9 and 27, we need to sum up the probabilities for all x values between 9 and 27.

P(9 < X < 27) = P(X = 15) + P(X = 22)
= 0.16 + 0.40
= 0.56

Therefore, the probability that X is between 9 and 27 is 0.56.

d. To find the probability that X is greater than 19, we need to sum up the probabilities for all x values greater than 19.

P(X > 19) = P(X = 22) + P(X = 34) + P(X = 40)
= 0.40 + 0.25 + 0.19
= 0.84

Therefore, the probability that X is greater than 19 is 0.84.
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