Let's simplify the expression step by step:
The original expression is:
\[ z + \frac{6}{3^2} - (2 \times 3) + 5 \]
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Calculate \( 3^2 \): \[ 3^2 = 9 \]
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Now substituting it back in: \[ z + \frac{6}{9} - (2 \times 3) + 5 \]
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Simplify \( \frac{6}{9} \) (which reduces to \( \frac{2}{3} \)): \[ z + \frac{2}{3} - (2 \times 3) + 5 \]
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Calculate \( 2 \times 3 \): \[ 2 \times 3 = 6 \]
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Now substituting it back: \[ z + \frac{2}{3} - 6 + 5 \]
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Combine \( -6 + 5 \): \[ -6 + 5 = -1 \]
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Now substituting back: \[ z + \frac{2}{3} - 1 \]
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Rewrite \( -1 \) as \( -\frac{3}{3} \): \[ z + \frac{2}{3} - \frac{3}{3} \]
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Combine the fractions: \[ z + \left(\frac{2}{3} - \frac{3}{3}\right) = z - \frac{1}{3} \]
Thus, there is no denominator for the entire expression after simplification; however, if you're asking for the denominator from the fraction \( \frac{2}{3} \) that appeared in the calculation, it's 3.
The answer choices (8 and 26) do not relate to the simplified expression \( z - \frac{1}{3} \). Could you please confirm the question, as it seems your provided options don’t match the denominator present in the calculations? If you're looking for something else, please clarify!