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Consider the experiment of drawing two cards from a deck in which all picture cards have been removed and adding their values (...Asked by Rachael
Consider the experiment of drawing two cards from a deck in which all picture cards have been removed and adding their values (with ace = 1).
A. Describe the outcomes of this experiment. List the elements of the sample space.
B. What is the probabilit of obtaining a total of 5 for the two cards ?
C. Let A be the event "total card value is 5 or less." Find P (A) and P (Ac).
A. Describe the outcomes of this experiment. List the elements of the sample space.
B. What is the probabilit of obtaining a total of 5 for the two cards ?
C. Let A be the event "total card value is 5 or less." Find P (A) and P (Ac).
Answers
Answered by
Reiny
sample space:
cards --- sum
1 2 --3
1 3-- 4
1 4 --5
1 5 --6
1 6 --7
1 7 --8
1 8 --9
1 9 -- 10
1 10 -- 11 total outcome here is 9 , one with a sum of 5
2 3 --5
2 4 -- 6
..
2 10 -- 12 total outcome here is 8 , one with a sum of 5
3 4
3 5
..
3 10 -- total outcomes here is 7, no sum of 5 possible
....
9 10 -- one outcome, no sum of 5
total number of outcomes:
9+8+7+6+5+4+3+2+1 = 45
cases where the sum is 5 is 2
B) prob of sum of 5 = 2/45
C) to get a sum of 5 or less, I see only 4 cases
prob (5 or less) = 4/45
don't know what you mean by P (Ac)
cards --- sum
1 2 --3
1 3-- 4
1 4 --5
1 5 --6
1 6 --7
1 7 --8
1 8 --9
1 9 -- 10
1 10 -- 11 total outcome here is 9 , one with a sum of 5
2 3 --5
2 4 -- 6
..
2 10 -- 12 total outcome here is 8 , one with a sum of 5
3 4
3 5
..
3 10 -- total outcomes here is 7, no sum of 5 possible
....
9 10 -- one outcome, no sum of 5
total number of outcomes:
9+8+7+6+5+4+3+2+1 = 45
cases where the sum is 5 is 2
B) prob of sum of 5 = 2/45
C) to get a sum of 5 or less, I see only 4 cases
prob (5 or less) = 4/45
don't know what you mean by P (Ac)
Answered by
Rachael
Liked your answer, did not see it the first time, thanks!
Answered by
John
This can't be correct. There are four suits so wouldn't the sample space be 45 x 4 = 180??
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