Consider the events of drawing an ace, then draw another ace, followed by a queen, one at a time without replacement (from a standard deck of cards). What is the probability of drawing an ace, then another ace, then a queen?

Question

Consider the events of drawing an ace, then draw another ace, followed by a queen, one at a time without replacement (from a standard deck of cards). What is the probability of drawing an ace, then another ace, then a queen?
please show explanation

PsyDAG · Answer

First Ace = 4/52 Second Ace = 3/51 Queen = 4/50 If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.