consider the equilibrium reaction: pbcro4(s) <--> pb^2+ (aq) +cro4^2- (aq). A saturated solution of lead chromate, pbcro4 has a lead ion concentration of 1.4 x 10^-7 m. what is the value of the solubility product ksp for lead chromate?

Answer 1

See your post above.
.......PbCrO4(s) ==> Pb^2+ + CrO4^2-
E.......solid.......1.4E-7...1.4E-7
Substitute into the Ksp expression and solve for Ksp.