To complete the table of values for the equation \( y = \frac{x}{5} + 2 \), we can substitute the given \( x \) values into the equation.
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For \( x = -5 \): \[ y = \frac{-5}{5} + 2 = -1 + 2 = 1 \]
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For \( x = 0 \): \[ y = \frac{0}{5} + 2 = 0 + 2 = 2 \]
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For \( x = 5 \): \[ y = \frac{5}{5} + 2 = 1 + 2 = 3 \]
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For \( x = 10 \): \[ y = \frac{10}{5} + 2 = 2 + 2 = 4 \]
Now we can fill in the blanks in the table:
| x | y | |-----|-----| | -5 | 1 | | 0 | 2 | | 5 | 3 | | 10 | 4 |
Thus, the completed table of values is:
\[ \begin{array}{|c|c|} \hline x & y \ \hline -5 & 1 \ 0 & 2 \ 5 & 3 \ 10 & 4 \ \hline \end{array} \]
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