I would reduce it to
y'=(y-x)/(4y-x)
Consider the equation:
x^2 - 2xy + 4y^2 = 64
Write an expression of the slope of the curve at any point.
(y^p)= y prime
My work
2x - 2(xy^p + y) + 8yy^p = 0
2x -2xy^p - 2y + 8yy^p = 0
-2xy^p + 8yy^p = 2y -2x
factored out y^p and then divided to get
(2y - 2x) / (8y - 2x)
Which I think is wrong.
Please let me know where I went wrong if I did.
2 answers
Ok, so it was right at first. Thanks for the further simplifying. :)