v = 1/4 zxt^2
z = 4v / xt^2
= (L/T) / (LT^2)
= 1/T^3
Consider the equation
v = (1/4)zxt^2.
The dimensions of the variables v, x, and t are [L]/[T], [L], and [T], respectively. The numerical factor 4 is dimensionless. What must be the dimensions of the variable z, such that both sides of the equation have the same dimensions?
2 answers
L/T = zLT^2
L/T รท LT = zT
1/T^2 = zT
1/T^3 = z
L/T รท LT = zT
1/T^2 = zT
1/T^3 = z
3 answers