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f' = 7 e^7x - e^-x
when is that zero?
7 e^7x = e^-x
7 e^8x = 1
e^8x = 1/7
8 x = ln(1/7)
x = -.243 at min
consider the equation below
f(x)=e^(7x)+e^(-x)
find the intervals on which f is increasing and decreasing (enter your answers using interval notation)
find the local minimum of f.
find the interval on which f is concave up.
1 answer
1 answer