Let the point be (h,k)
The distance d is thus
d^2 = x^2 + (y-1)^2
but, we know that x^2 = 9 - 9y^2, so
d^2 = 9-9y^2 + (y^2-2y+1)
= 10 - 2y - 8y^2
dd/dy = -2 - 16y = -2(1+8y)
so, y = -1/8
and you can get x
Consider the ellipse plotted by x^2+9y^2=9. Find the y-coordinate of the point on the ellipse that is farthest from the point (0,1).
Your answer should be expressed as a fraction of whole numbers.
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