Kc = kf/kr = ?
See this link
https://chem.libretexts.org/Bookshelves/General_Chemistry/Map%3A_A_Molecular_Approach_(Tro)/15%3A_Chemical_Equilibrium/15.02%3A_The_Equilibrium_Constant_(K)
Consider the elementary reactions and their rate constants.
A(g)+B(g)âķC(g)+D(g) ðð=5.72Ã10â^2 s^â1
C(g)+D(g)âķA(g)+B(g) ðð=2.60Ã10â^1 s^â1
What is the equilibrium constant ( ðūc ) of the following generic reaction?
A(g)+B(g)â―âââC(g)+D(g)
I'm not really sure how to begin to solve this question?
2 answers
This is actually really easy to solve and all you have to do is plug in the given equations into
Kc=kf/kr
Kc= (5.72*10^-2 s^-1)/ (2.60*10^-1 s^-1)
Kc=kf/kr
Kc= (5.72*10^-2 s^-1)/ (2.60*10^-1 s^-1)