dy/dx = -2x/y
y dy = -2x dx
1/2 y^2 = -x^2 + C
since y(1) = 1
-1+C = 1/2
C = 3/2
y^2 = -2x^2 + 3
Consider the differential equation dy/dx=-2x/y
Find the particular solution y =f(x) to the given differential equation with the initial condition f(1) = -1
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