I'm sure you know the equation for the H2.
2H^+ + 2e ==> H2(g)
E=Eo-(0.059/n)*log(pH2/H^+) but you need to add the partial pressures and concentrations to that. Here is a site you can read about the SCE.
http://en.wikipedia.org/wiki/Saturated_calomel_electrode
consider the cell
Pt(s)I H2 (g. 0.100 bar)I H+ (aq, pH= 2.54)IICl^- ( aq, 0.200 MI Hg2Cl2(S)IHg (l)IPt(s)
a. write a reduction reaction and nernst equation for each half- cell. For the Hg2Cl2 half reaction, E^0 = 0.268 V
b. Find E for the net cell reaction and state whether reduction will occur at the left ot right hand electrodes
1 answer
1 answer