Consider the 690 N weight held by two cables. The left-hand cable had tension T2 and makes an angle of 41◦ with the ceiling. The right-hand cable had tension T1 and makes an angle of 42◦ with the ceiling.

Answer 1

first figure the angles the verticalmakes with the cables.
Left=49
right:48

Sum of vertical forces is zero.
690-L*cos49 -R*cos48=0

put that into the form
a*L + b*R=c

then second equation: sum horizontal forces is zero.
L*sin49-R*sin48=0

so you have two equations, two unknowns, solve for L, and R

Answer 2

Thanks!