a. -T2*Cos44 + T1*Cos42 = 0.
T1*Cos42 = T2*Cos44.
T2 = 1.033T1.
T2*sin44 + T1*sin42 = -(-608) = 608 N.
1.033T1*sin44 + T1*sin42 = 608.
0.718T1 + 0.669T1 = 608.
1.39T1 = 608.
T1 = 438.3 N.
b. T2 = 1.033 * 438.3 = 452.8 N.
Consider the 608 N weight held by two cables shown below. The left-hand cable had ten- sion T2 and makes an angle of 44◦ with the ceiling. The right-hand cable had tension T1 and makes an angle of 42◦ with the ceiling.
a) What is the tension in the cable labeled T1 slanted at an angle of 42◦?
Answer in units of N.
(part 2 of 2) 10.0 points
a) What is the tension in the cable labeled T2 slanted at an angle of 44◦?
Answer in units of N.
1 answer