To show that triangles \( \Delta ABC \) and \( \Delta XYZ \) are congruent using the Hypotenuse-Leg (HL) Congruence Theorem, we need to establish that two of their corresponding sides are congruent besides the congruent hypotenuses (which are \( AC \) and \( XZ \)) and the congruent angles (angle \( B \) and angle \( Y \)) that are given.
Since the hypotenuses \( AC \) and \( XZ \) are already stated to be congruent, and we know that angles \( B \) and \( Y \) are congruent, we can conclude two triangles are congruent if one other leg is proven congruent.
The correct corresponding part that must be congruent is:
BC̅̅̅̅̅̅ ≅ XZ̅̅̅̅̅̅.
So the complete answer is that you must show that \( BC \) (one leg of triangle \( \Delta ABC \)) is congruent to \( XY \) (the corresponding leg of triangle \( \Delta XYZ \)). This satisfies the requirements of the HL theorem.
Therefore, the answer is:
BC̅̅̅̅̅̅ ≅ XY̅̅̅̅̅̅.