Consider right triangles ΔABC and ΔXYZ . Angle B and angle Y are congruent. The hypotenuse of each triangle is AC¯¯¯¯¯¯¯¯ and XZ¯¯¯¯¯¯¯¯ , and they are congruent. What other corresponding parts must be congruent to show that ΔABC≅ΔXYZ by the HL Congruence Theorem?(1 point)

Responses

BC¯¯¯¯¯¯¯¯≅XZ¯¯¯¯¯¯¯¯
Modifying above upper B upper C with bar congruent to Modifying above upper X upper Z with bar

AB¯¯¯¯¯¯¯¯≅XY¯¯¯¯¯¯¯¯
Modifying above upper A upper B with bar congruent to Modifying above upper X upper Y with bar

AB¯¯¯¯¯¯¯¯≅YZ¯¯¯¯¯¯¯
Modifying above upper A upper B with bar congruent to Modifying above upper Y upper Z with bar

BC¯¯¯¯¯¯¯¯≅XY¯¯¯¯¯¯¯¯
Modifying above upper B upper C with bar congruent to Modifying above upper X upper Y with bar
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1 answer

To show that triangles \( \Delta ABC \) and \( \Delta XYZ \) are congruent using the Hypotenuse-Leg (HL) Congruence Theorem, we need to establish that two of their corresponding sides are congruent besides the congruent hypotenuses (which are \( AC \) and \( XZ \)) and the congruent angles (angle \( B \) and angle \( Y \)) that are given.

Since the hypotenuses \( AC \) and \( XZ \) are already stated to be congruent, and we know that angles \( B \) and \( Y \) are congruent, we can conclude two triangles are congruent if one other leg is proven congruent.

The correct corresponding part that must be congruent is:

BC̅̅̅̅̅̅ ≅ XZ̅̅̅̅̅̅.

So the complete answer is that you must show that \( BC \) (one leg of triangle \( \Delta ABC \)) is congruent to \( XY \) (the corresponding leg of triangle \( \Delta XYZ \)). This satisfies the requirements of the HL theorem.

Therefore, the answer is:

BC̅̅̅̅̅̅ ≅ XY̅̅̅̅̅̅.